Matematika 100²-99²=(100²-98²)=1(196) 99²-972=(99+97)(99-97)=2(198) 4²-2²=2(6) 3²-1²=2(4)b

jermaineblandaulv – March 10, 2023

100²-99²=(100²-98²)=1(196)
99²-972=(99+97)(99-97)=2(198)
4²-2²=2(6)
3²-1²=2(4)b

Jawaban:

100B = 2 (4) + 2 (6) + 2 (12) + 2(14) + 2(20) + 2(22) +...+ 2 (196) + 2(198)

Sekarang kita pisahkan

2(4) + 2(12) + 2( 20) + 2(28) +...+ 2(196) =

4 (2 + 6 + 10 + 14+...+ 98) =

98 = 2 + 4 (n-1)

96 = 4 (n-1)

25 = n

2 + 6 + 10 + 14 +...+ 98 = 25 (2 + 98) / 2 = 1250

4(2+6+10+14+...+98) = 4 x 1250 = 5000

Selanjutnya

2 (6) + 2(14) + 2(22) + ...+ 2 (198) =

4 (3 + 7 + 11 +...+99) =

4 ( 25 (3 +99) / 2) = 5100

Penjelasan dengan langkah-langkah:

hh

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